Question

a girl did half of some work on Monday & one third of it on Tuesday. how much will she have to do on Wednesday in order to complete the work?

topic: fractions
please say me the ans::​

Answer 1

Given

Half of work is done on Monday and one-third on Tuesday by a girl

Let total work done by a girl is 1

Work done on Monday = 1 / 2

Work done on Tuesday = 1 / 3

Hence, remaining work done on Wednesday to complete the work is calculated as below

Remaining work done = 1 – [(1 / 2 + 1 / 3)]

Taking LCM, we get

= 1 – [(3 + 2) / 6]

= 1 – 5 / 6

= (6 – 5) / 6

= 1 / 6

Hence, work done by a girl on Wednesday to complete is 1 / 6

hope it helps

Answer 2

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Given:

a girl did half of some work on Monday & one third of it on Tuesday. how much will she have to do on Wednesday in order to complete the work?

Answer:

work done on Wednesday = 1/0 of work

Explanation:

$let \: total \: work \: done \: = \: 1 \\ work \: done \: on \: monday \: = \: \frac{1}{2} \\ work \: done \: on \: tuesday \: = \: \frac{1}{3} \\ work \: done \: on \: wednesday \: = \: remaining \: work \\ = 1 - ( \frac{1}{2} + \frac{1}{3} ) \\ = 1 - \frac{3 + 2}{6} = 1 - \frac{5}{6} \\ = \frac{6 - 5}{6} \\ work \: done \: on \: wednesday \: = \: \frac{1}{0} of \: work$