Question

A girl exerts a pressure of 500 newton on the floor. The area of cross section of one of her heel is 1cm.sq. find the pressure exerted by both of her heels on the floor

Answer 1

Explanation:

thrust = 500 N

area = 1cm sq

= 1/10000 m sq

pressure exerted by her = 500/1/10000 ×2

=5 × 10 to the power 6 × 2

=10× 10 to the power 6 pascal