A girl has Rs 300 which consists of the denominations of rs 1 coins,rs 2 coins and rs 5 coins.The number of rs 2 coins is three times the number of rs 5 coins.The total sum of all the coins is 160.Find the number of each denominations.
Answers
Hello mate!✌
Let the no.of Rs.5 coin be x
No.of Rs.1 coin be y
No.of Rs.3 coin be 3x
Total no.of coins = 160
x + 3x + y = 160
4x + y = 160 eq.1
Total value of coins = 300
5x + 2(3x) + y = 300
11x + y = 300 eq.2
by elimination method
on subtracting both the equations
4x + y = 160
-11x - y = -300
-7x = -140
x = 20
on putting the the value of x in eq 2
4(20)+y = 160
80+y = 160
y = 160 -80
y = 80
now,
no of rs 2 coins = 3(20)
= 60
no. of rs 5 coins = 20
no. of rs 1 coins=80
Hope this helps
@adiba31☺❤
Answer:
Step-by-step explanation:
Let no. of Rs. 1 coins = x
and
No. of Rs. 5 coins = y
Given, no. of Rs. 2 coins = 3 times no. of rs. 5 coins
==> no. of Rs. 2 coins = 3y
Total money = Rs 300
==> 1*x + (2*3y) + (5*y) = 300 (rupees = denominations * total no of coins)
==> x + 6y + 5y = 300
==> x+11y = 300 ...........................equation 1
Also given, sum of coins = 160
==>x + 3y + y = 160
==> x+4y = 160..................................equation 2
Subtracting equation 1 and 2:
7y = 140
==>y=20 ....................no. of Rs. 5 coins
No. of Rs. 2 coins = 3y = 3*20 = 60
Therefore, No. of Rs. 1 coin = 160-(20+60) = 80