A girl having a mass of 40kg sits on a trolley of a mass 80kg. The trolley is given an initial velocity of 5m/s by applying a force. The trolley comes to rest after travelling a distance of 15m. How much work is done on the trolley and how much work is done by the girl.
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Answer:
mass of girl m=35kg
mass of trolley=5kg
total mass=40kg
initial velocity of trolley u=4ms
−1
final velocity of trolley v=0ms
−1
distance s=16m
we know,
v
2
−u
2
=2as
a=
2s
v
2
−u
2
=−
2×16
16
a=−
2
1
ms
−2
Force=ma=40×(−0.5)
=-20N
work is done on the trolley=20N×16m=320 J.
work was done by the girl =0 J.
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