A girl having mass 35kg sits on trolley of mass 5 kg . The trolley is given an initial velocity of 4 m/s by applied a force. The trooly comes to rest after travelling the distance of 16 m . How much work done on the trolley
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u=4 v=0 s=16m force=mass×acceleration
0-4×4=2×16×a
-16=32a
a=-2
force=35×-2=-70
work done=force×displacement
=-70×16
=-1120
0-4×4=2×16×a
-16=32a
a=-2
force=35×-2=-70
work done=force×displacement
=-70×16
=-1120
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