Question

A girl having mass of 35 kg sits on a trolley of mass
5 kg. The trolley is given an initial velocity of
4 msl by applying a force. The trolley comes to
rest after traversing a distance of 16 m. (a) How
much work is done on the trolley ?
​

Answer 1

Answer:

-320 J

Explanation:

Given,

Mass of girl=35 kg

Mass of Trolley(m)=5 kg

Total mass=40 kg

Now, by third equation of motion:

v²=u²+2as

0=4²+2(a)(16)

0=16+32a

-32a=16

a=16/-32

a=-0.5 m/s²

Now,

F=Total mass× a

F=40×-0.5

F=-20 N

a.) Work done on trolley=F×S×COS 180°

W.D=20×16×-1

W.D=-320 Joules.

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Answer 2

Answer:320 j

Explanation:Given,

Mass of girl=35 kg

Mass of Trolley(m)=5 kg

Total mass=40 kg

Now, by third equation of motion:

v²=u²+2as

0=4²+2(a)(16)

0=16+32a

-32a=16

a=16/-32

a=-0.5 m/s²

Now,

F=Total mass× a

F=40×-0.5

F=-20 N

a.) Work done on trolley=F×S×COS 180°

W.D=20×16×-1

W.D=-320 Joules.

Hope it helps you!

Please mark me as the brainliest