a girl if mass 40 kg sit on the trolley of mass 5kg. The initial speed of the trolley is 5 metre per second when the force is applied the trolley comes to the rest after travelling the distance of 10.(1) find the work done on the trolley.(2)find the work done by the girl on the trolley.
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Answer:
mass of girl m=35kg
mass of trolley=5kg
total mass=40kg
initial velocity of trolley u=4ms−1
final velocity of trolley v=0ms−1
distance s=16m
we know,
v2−u2=2as
a=2sv2−u2
=−2×1616
a=−21ms−2
Force=ma=40×(−0.5)
=-20N
work is done on the trolley=20N×16m=320 J.
work was done by the girl =0 J.
Explanation:
pls mark me as brainliest answer dont cheat
sarthakmaharia:
35 is not there
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