A girl is 27 years younger than her father. in 3 years’ time, the sum of their ages will be 51. how old are they now? Show full working
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Let us take the age of father be x.
Then the age of the daughter =x-27.
Age of father after 3 yrs. = x+3
Age of daughter after 3 yrs. = x-27+3=x-24yrs.
Sum of ages = x +3 +x -24=2x -21.
But it is given 51 yrs.
So,
Atq, 2x -21=51.
or 2x =51+21
or 2x = 72
Therefore x =36.
Age of father =x =36yrs.
Age of daughter = x-27 =36-27=9 yrs.
Then the age of the daughter =x-27.
Age of father after 3 yrs. = x+3
Age of daughter after 3 yrs. = x-27+3=x-24yrs.
Sum of ages = x +3 +x -24=2x -21.
But it is given 51 yrs.
So,
Atq, 2x -21=51.
or 2x =51+21
or 2x = 72
Therefore x =36.
Age of father =x =36yrs.
Age of daughter = x-27 =36-27=9 yrs.
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