A girl is 28 years younger than her father.the sum of their age is 50 years,find their ages
Answers
Answered by
2
Answer:
39-father,11-daughter
Step-by-step explanation:
let dad's age be 'a' an girl's age be 'b'
=> a - 28 = b
a - b = 28....(1)
a + b = 50...(2)
adding (1) and (2) we get,
2a = 78
a = 39
39 + b = 50….from (2)
b = 11
Answered by
2
Answer:
∴ Father=39 years
Girl=39-28
= 11 years
Step-by-step explanation:
Father =x
Girl = x-28
x+x-28=50
2x-28=50
2x=50+28
2x=78
x=78/2
x=39
∴ Father=39 years
Girl=39-28
= 11 years
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