Question

a girl is 28 years younger than her father the sum of their ages is 50 years find the ages of the girl and her father

Answer 1

◀HERE'S YOUR ANSWER▶

Let, the age of the father = x years.

Then, his daughter is (x - 28) years old.

Given that,
x + (x-28) = 50
⏩ 2x - 28 = 50
⏩ 2x = 78
⏩ x = 39

So, the father is 39 years old and the daughter is 11 years old.

HOPE THIS HELPS

Answer 2

Hi there !!

Let the father's age be x

The girl is 28 years younger than her father,

Girl's age = x - 28 years

Also,
Sum of ages of father and daughter is 50 years,

So,
the following balanced equation will be formed

$x + x - 28 = 50$
adding x and x in LHS and transposing -28 to RHS,
we have,

$2x = 50 + 28$

$2x = 78$

$x = \frac{78}{2}$
x = 39

So,

Father's age = x = 39 years

Girl's age = x - 28 = 39 - 28 = 11 years