Question

A girl is 28 years younger than her father. The sum of their ages is 50 years . find the ages of the girl and her father 1. 11 and 39 2. 12 and 38 years 3. 10and 40 years 4. none of these​

Answer 1

Answer:Let x be the age of dather

Thus, age of his girl =(x−28) years

ACQ,

⇒ x+x−28=50

⇒ 2x=50+28

⇒ 2x=78

⇒ x=  

2

78

​

 

⇒ x=39

Therefore, age of father is 39 years and age of his daughter is 11 years.

Answer 2

question :-

A girl is 28 years younger than her father. The sum of their ages is 50 years . find the ages of the girl and her father ??

answer :-

let the girl's age be (X + 28) years

let the father's age be x years

$⇢ \: x + x - 28 = 50$

$⇢ \: 2x - 28 = 50$

$⇢ \: 2x = 50 + 28$

$⇢ \: 2x = 78$

$⇢ \: x = \cancel\dfrac { 78 } { 2 }$

$⇢ \: x = 39$

so therefore Father age is 39 years

girl age is X - 28 = 39 - 28 = 11 is the girl's age