A girl is 28 years younger than her father. The sum of their ages is 50years . find the ages of the girl and her father
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Let girl's father age be x years.
girl age be x-28 years.
sum of their age is 50 years .
x+x-28=50
2x-28=50
2x=50+28
2x=78
x=78/2
x=39
father's age is 39 years.
girl's age is 39-28=11 years.
girl age be x-28 years.
sum of their age is 50 years .
x+x-28=50
2x-28=50
2x=50+28
2x=78
x=78/2
x=39
father's age is 39 years.
girl's age is 39-28=11 years.
Answered by
3
Given :
A girl is 28 years younger than her father sum of their age's is 50.
To find:
The ages of the girl and her father?
Solution :
Let her father's age is X
Let the girl's age is X - 28
Given sum = 50
According to the given question :
=> x+ x-28 = 50
=> 2x-28= 50
=> 2x = 50+28
=> 2x = 78
=> X= 78/2
=> X = 39
Hence father's age is X = 39 years
Girl age is x-28 = 39-28 = 11 years.
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