Question

A girl is 28 years younger than her father. The sum of their ages is 50years . find the ages of the girl and her father

Answer 1

Let girl's father age be x years.
girl age be x-28 years.
sum of their age is 50 years .

x+x-28=50
2x-28=50
2x=50+28
2x=78
x=78/2
x=39

father's age is 39 years.
girl's age is 39-28=11 years.

Answer 2

Given :

A girl is 28 years younger than her father sum of their age's is 50.

To find:

The ages of the girl and her father?

Solution :

Let her father's age is X

Let the girl's age is X - 28

Given sum = 50

According to the given question :

=> x+ x-28 = 50

=> 2x-28= 50

=> 2x = 50+28

=> 2x = 78

=> X= 78/2

=> X = 39

Hence father's age is X = 39 years

Girl age is x-28 = 39-28 = 11 years.