Math, asked by Joses2239, 9 months ago

A girl is 28 years younger than the father.the sum of their ages is 50 years.
Find the ages of the girl and her father how to solve the problem

Answers

Answered by ButterFliee
2

Answer:

let the age of girl be x years

and father be (x+ 28)

ATQ

x + x + 28 = 50

2x = 50-28

2x = 22

x= 11

father's age = (x + 28)= 11+ 28 = 39

hope it will help you

Answered by ihrishi
0

Step-by-step explanation:

Let the father's age be x years

Hence, girl's age = (x - 28) years

According to the given condition:

x + (x- 28)= 50

2x - 28 = 50

2x = 50 + 28

2x = 78

\therefore x = \frac{78}{2}\\</p><p>\therefore x = 39\\</p><p>\therefore x - 28 = 39 - 28 = 11

Therefore,

Father's age = 39 years.

Girl's age = 11 years.

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