Question

A girl is carrying a school bag of 3 kg mass on her back and moves 200 m on a levelled road.The work done against the gravitational force will be (g = 10 ms²) *​

Answer 1

Answer:

Answer is zero.

The amount of work done is expressed in the equation: workdone=force×distance. In this case, the total work done is zero as the displacement is perpendicular to the applied force.

Answer 2

Given :-

Mass of the school bag = 3 kg

Horizontal displacement of girl = 200 m

To Find :-

The work done against the gravitational force.

Analysis :-

Here we are given with the mass and the horizontal displacement of the girl.

In order to find the work done substitute the values given in the question such that work done is equal to mass into gravity into height.

Solution :-

We know that,

• m = Mass
• h = Height
• g = Gravity
• w = Work done

Using the formula,

$\underline{\boxed{\sf Work \ done=Mass \times Gravity \times Height}}$

Given that,

Mass (m) = 3 kg

Gravity (g) = 10 m/s

Height (h) = 0 (displacement is perpendicular to the applied force)

Substituting their values,

⇒ w = mgh

⇒ w = 3 × 10 × 0

⇒ w = 30 × 0

⇒ w = 0 J

Therefore, the work done against the gravitational force is 0 J.