A girl is observing a ball from the balcony which is 30 metre above from the ground and the angle of depression of the ball is alpha such that sec 2 alpha equal to cos alpha. Find the distance of line of sight of the ball.
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Distance of line of sight of the ball. = 30√2 m
Step-by-step explanation:
Sinα = BC/AC
=> Sinα = 30/AC
=> AC = 30/Sinα
AC = distance of line of sight of the ball.
Sec2α = Cosα
there seems some mistake in data
as Range of Cos is less than 1 ( only considering + ve values)
& Range of Sec is more than 1 ( only considering + ve values)
only possible value of α = 0°
Hence mistake in data
it should be
Secα = Cosecα
=> α = 45°
Sin45° = 1/√2
AC = 30/(1 /√2) = 30√2 m
distance of line of sight of the ball. = 30√2 m
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