Math, asked by siddharthchandel2004, 11 months ago

A girl is observing a ball from the balcony which is 30 m above from the ground (see the below
figure) and the angle of depression of the hall is a such that sec3a-cosec2a, find the distance
of line of sight of ball

Answers

Answered by amitnrw
1

the distance of line of sight of ball​. = 100 m

Step-by-step explanation:

Sec3A - Cosec2A = 0

=> Sec3A = Cosec2A

=> 1/Cos3A = 1/Sin2A

=> Sin2A  = Cos3A

=> Sin2A = Sin(90 - 3A)

=> 2A = 90 - 3A

=> 5A = 90

=> A = 18

SinA = BC/AC

=> AC = BC/Sin18

=> AC = 30/Sin18

=> AC = 30/0.3

=> AC = 100

the distance of line of sight of ball​. = 100 m

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Attachments:
Answered by Roger290404
0

Sec3A - Cosec2A = 0

=> Sec3A = Cosec2A

=> 1/Cos3A = 1/Sin2A

=> Sin2A = COS3A

=> Sin2A = Sin(90 - 3A)

=> 2A = 90 - 3A

=> 5A = 90

=> A = 18

SinA = BC/AC

=> AC = BC/Sin18

=> AC = 30/Sin18

=> AC = 30/0.3

=> AC = 100

the distance of line of sight of ball. = 100

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