Question

a girl is running in a race accleration at 2.5 m s-2 for first 4 second of the race how far does she travel in this time

Answer 1

Here 's your answer..

Solution:-

Acceleration is given = 2.5m/s^2
Initial Velocity=0
Time =4seconds

Now,
We'll find the distance travelled by him by using equation,that is,
$= > s = ut + \frac{1}{2} {at}^{2} \\ = > s = 0 \times 5 + \frac{1}{2} \times 2.5 \times {(4)}^{2} \\ = > s = 0 + \frac{1}{2} \times 2.5 \times 16$
$= > s = 2.5 \times 8 \\ = > s = 20$

Therefore,
Distance travelled is 20m.

Hope it helps you....