Question

A girl is twice an old as her sister .Five years hence,the product of their ages (in years) will be 375 .Find their present ages.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Let her sister's age= x

Let here age = 2x

After 5 years ,the product of their ages=375

(x+5)(2x+5)=375

x(2x+5)+5(2x+5)=375

2x²+5x+10x+25=375

2x²+15x+25=375

2x²+15x=375-25=350

2x²+15x-350=0

splitting the middle term

2x²+(35x-20x)-350

2x²+35x-20x-350

x(2x+35)-10(2x+35)

(x-10)(2x+35)

These values should make up 'x'

by equating 0

x-10=0

x=0+10=10

2x+35=0

2x=0-35

2x=-35

x=-35/2

we know age can't be less than 0,that is not be negative therefore x=10

her sister's age=x=10

her age=2x=2×10=20

hope it helps