Question

a girl is twice as old as her sister.four years hence the product of their ages will be 160 years. find their present ages.​

Answer 1

Answer:

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LET, PRESENT AGE OF THE GIRL =2X

AGE OF HER SISTER =X

ACCORDING TO THE QUESTION

(2X+4)(X+4)=160

2X^2+8X+4X+16=160

2X^2+12X-144=0

2X^2+(24-12)X-144=0

2X(X+12)-12(X+12)=0

(2X-12)(X+12)=0

X=6;X=-12

(NEGLECT NEGATIVE VALUES)

SO ,AGE OF GIRL=12

AGE OF SISTER=6