Question

A girl is twice as old as her sister. Four years hence the product of their ages will be 60. Find their present ages.

Answer 1

You have done some mistakes in your question, The correct question is =>

Q: A girl is twice as old as her sister. Four years hence the product of their ages will be 160. Find their present ages.

Solutions :-

Let the age her sister be x
Girl's age = 2x

After four years,
Her sister's age = x + 4
Girl's age = 2x + 4

Product of their age = 160 years


According to the question,

=> (x + 4) (2x + 4) = 160
=> x (2x + 4) + 4(2x + 4) = 160
=> 2x² + 4x + 8x + 16 = 160

Now divide each term by 2. We get,
=> x² + 2x + 4x + 8 = 80
=> x² + 6x + 8 - 80 = 0
=> x² + 6x - 72 = 0
=> x² + (12 - 6)x - 72 = 0
=> x² + 12x - 6x - 72 = 0
=> x(x + 12) - 6(x + 12) = 0
=> (x - 6) (x + 12) = 0
=> x = 6, - 12 (Age always taken positively)


Hence,
Sister's age = x = 6 years
Girl's age = 2x = 2 × 6 = 12 years

_______________________

✯ @shivamsinghamrajput ✯

Answer 2

here is your answer OK ☺☺☺☺☺☺

let assume age of girl sister = 2x

so girl sister age = x

so according to the question..................

(2x +4 )(x +4 ) = 160

2x'2+8x+4x +16 = 160
2x'2+12x -144= 0
2x'2+(24-12)x-144=0

(2x-12) (x+20)= 0

x = 6.
2x = 12

age of girl = 12
age of girl sister = 6

thanks for asking this ☺☺☺☺☺question


&&be brainly.....