A girl leaves her home every day at 10:00 am and reaches office at 11 am. one day she leaves home at normal time and travelled the first half of the distance at the 2/3 of her original speed, at what speed should she travel at the 2nd half so that she reaches office on time.
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a group leaves at 10.00am
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Step-by-step explanation:
She'll at 9.25 am. She'll take 85 minutes
Step-by-step explanation:
regular speed is x/ninety kms consistent with minute.
1/three of the gap is travelled in three/four of the speed. therefore time taken is 40 mts. 2/3 is travelled
in 45 mts. therefore 85 mts.
Hope it helps
:)
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