A GIRL LIFTS A MASS OF 25 Kg TO A HEIGHT OF 50 cm, IF 'g' = 10 m/s^2, HOW MUCH WORK DID SHE DO ON THE OBJECT?
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Answered by
1
Answer:
zero work
Explanation:
W=FScostheta
here theta is angle between force and displacement..... which here is zero. therefor cos0=0.......so W=0
Answered by
1
Answer:
125J
Explanation:
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