Physics, asked by Anonymous, 9 months ago

A GIRL LIFTS A MASS OF 25 Kg TO A HEIGHT OF 50 cm, IF 'g' = 10 m/s^2, HOW MUCH WORK DID SHE DO ON THE OBJECT?
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Answers

Answered by ECHAYAN

1

Answer:

zero work

Explanation:

W=FScostheta

here theta is angle between force and displacement..... which here is zero. therefor cos0=0.......so W=0

Answered by abhaypatel12345

1

Answer:

125J

Explanation:

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