Question

A girl moves 500m in 2 minutes and next 1000m in 30s on the same straight path. What is her average speed and average velocity?

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Answer 1

Explanation:

⏪GIVEN⏩

A girl moves 500 m in 2 minutes and next 1000 m in 30 seconds on the same straight path.

⏪TO FIND⏩

The average speed and the average velocity of the girl.

⏪ FORMULAS TO BE USED ⏩

▪ Average speed = Total distance covered/Total time taken

▪ Average velocity = Overall displacement/Total time taken

▓▓▓ SOLUTION ▓▓▓

As the girl moves in a straight path without taking any U-turns or changing its direction, so displacement = distance.

⇒Displacement/Time = Distance/Time

⇒Velocity = Speed

⇒Average velocity = Average speed

Now,

➡Total length of the path covered = 500 + 1000 = 1500 m

➡Total time taken = (2 × 60) + 30 = 120 + 30 = 150 s

Average velocity = Average speed = 1500/150

⇒Average velocity = Average speed = 10 m/s

Therefore, the average speed of the girl is same as the average velocity of the girl, that is 10 m/s..

Answer 2

$\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}$

$\sf{\underline{\pink{Answer-}}}$

• The average speed of the girl is same as the average velocity of the girl, that is 10 m/s.

$\sf{\underline{\pink{Given-}}}$

• A girl moves 500m in 2 minutes and next 1000m in 30s on the same straight path.

$\sf{\underline{\pink{We\:Have\:To\:Find-}}}$

• Herr average speed and average velocity.

$\sf{\underline{\pink{Explanation-}}}$

Total length of the path—

= 500 + 1000

= 1500 m

Time taken to cover the path—

= (2 × 60) + 30

(Multiplied by 60 because we have to change in seconds.)

= 120 + 30 = 150 s

$\sf{\underline{\pink{As\:We\: Know-}}}$

Average velocity = Average speed

(As she is traveling in straight line).

$\sf = \frac{1500}{150}$

$\sf \: = 10m/s$

Her average speed is same as the average velocity.

Thus,

• Average speed = 10m/s.

• Average velocity = 10m/s.