A girl moves a distance of 9m towards south, and she turns and moves 6m towards east.Claculate. 1)Total distance.2)Net displacement
Answers
Provided that:
✡️ A girl moves a distance of 9 metres towards the south. (s)
✡️ Then the girl turns and moves 6 m towards the east. (s′)
To calculate:
- Total distance
- Net displacement
Solution:
- Total distance = 15 m
- Net displacement = 10.81 m
Knowledge required:
✡️ Direction chart: Kindly refer to the attachment first!
Using concepts:
- Total distance formula
- Phythagoras theorm
Using formulas:
✴️ Formula to calculate the total distance is mentioned below:
- Total distance = s + s′
✴️ Phythagoras theorm is mentioned:
- (H)² = (P)² + (B)²
Where, P denotes perpendicular, B denotes base and H denotes height.
Required solution:
a. Firstly let us calculate the total distance by using suitable formula!
→ Total distance = s + s′
→ Total distance = 9 + 6
→ Total distance = 15 m
b. Now let us calculate the net displacement by using suitable formula!
→ (H)² = (P)² + (B)²
→ (H)² = (9)² + (6)²
→ (H)² = 81 + 36
→ (H)² = 117
→ H = √117
→ H = 10.81 m
→ Net displacement = 10.81 m
