A girl moves along the boundary of a square field of side 20m in 80s . What will be the magnitude of displacement at the end of 200s ? Also calculate the average velocity.
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perimeter of the field =4×20m=80m(in 80 secs)
. ' .she covers 200m in 200 secs
. ' .displacement after 200 secs=diagonal of the square=20m
avg velocity=total displacement/total time
=20/200=0.1m/s
. ' .she covers 200m in 200 secs
. ' .displacement after 200 secs=diagonal of the square=20m
avg velocity=total displacement/total time
=20/200=0.1m/s
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