Question

a girl moves with the speed of 60 km per hour for 2 hours and with the speed of 4 km per hour for the next 3 hours find the average speed of the girl and the total distance moved​

Answer 1

$v = \frac{d}{t} \\ 60 = \frac{d}{2} \\ d = 120km \\ \\ v = \frac{d}{t} \\ 4= \frac{d }{3} \\ d = 12km \\ \\ so \: av.sp = \frac{t.d}{t.t} \\ av.sp = \frac{120 +12 }{4 + 2} \\ = \frac{136}{6} \\ = 22.6666$

Answer 2

Speed 1 = 60 km/hr

Time 1 = 2 hr

Speed 2 = 4 km/hr

Time 2 = 3 hr

d1=60×2

d1=120km

2d2= speed 2× time 2

d2=4×3

d2=12 km

Total distance covered = d1 + d2

Total distance d = d1 + d2

d = 12 + 120

d = 132km

Total time t = time1 + time2

t = 2 + 3

t = 5 hr

Average speed = Total distance / Total time=d/t

132/5

=26.4km/hr

i hope this is right