Question

A girl obtained 738 marks out of 900 and her friend obtained 528 marks out of 600.Whose performance is better?​

Answer 1

➤ Given :-

Marks obtained by girl (1) :- 738

Total marks in exam (1) :- 900

Marks obtained by girl (2) :- 528

Total marks in exam (2) :- 600

➤ To Find :-

Who had performed better in exam

➤ Formula required :-

${\large \tt \dashrightarrow \orange{\boxed{\tt \gray{\dfrac{Obtained \: marks}{Total \: marks} \times 100}}}}$

➤ Solution :-

First, we should find the percentage obtained by both the girls and then compare their percentage

Percentage of first girl :-

${\tt \longrightarrow \dfrac{738}{900} \times 100}$

${\tt \longrightarrow \dfrac{738}{\cancel{900}} \times \cancel{100} = \dfrac{738}{9}}$

${\tt \longrightarrow \cancel \dfrac{738}{9} = \boxed{\tt 82 \bf\%}}$

Percentage of second girl :-

${\tt \longrightarrow \dfrac{528}{600} \times 100}$

${\tt \longrightarrow \dfrac{528}{\cancel{600}} \times \cancel{100} = \dfrac{528}{6}}$

${\tt \longrightarrow \cancel \dfrac{528}{6} = \boxed{\tt 88 \bf\%}}$

Comparison :-

${\tt \longrightarrow 82 \: \: and \: \: 88}$

Here, 88 is greater than 82.

So,

${\tt \longrightarrow 82 \: \boxed{ < } \: 88}$

$\Huge\therefore$ Her friend had performed better than the girl.