Question

A girl of Feet 500 Newton has feet with the total area of 200 cm square. what pressure does she apply on the ground if she stands on both the feet ?​

Answer 1

Solution-

Given:

• $\rm{Force (F)={500 N}}$
• $\rm{Area (A)={200 {cm^2} = 200 × ({10^{-2}})^2= 200 × {10^{-4}}}}$

We know that,

Pressure $\sf =\dfrac{Force}{Area}$

$\sf\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\dfrac{500\:N}{200×{10^{-4}}m^2}$

$\sf\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=2.5×10^4N{m^{-2}}$

$\sf\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=25×10^3N{m^{-2}}$

Therefore, the pressure she applied on the ground is $\sf\red{25×10^3N{m^{-2}}}$