A girl of mass 25 kg running with a velocity of 10 m/s jumps on a stationary cart of mass 10 kg, so that they start moving together with a common velocity. Find this common velocity of the system.
Answers
m1 = 25 kg
v1 = 10 m/s
m2 = 10 kg
v2 = final velocity
= m1v1 + m2v2
25×10 + 10×0 = 25×v +10×v
= 250 + 0 = 25v + 10v
= 250 = 35 v
v = 250/35
v = 7.14285714286 m/s
(hope it helps ☺️ btw hi army, i am not sure about the answer bcz i am in grade 7
Given data : A girl of mass 25 kg running with a velocity of 10 m/s jumps on a stationary cart of mass 10 kg, so that they start moving together with a common velocity.
To find : The common velocity of the system ?
Solution :
⟹ Mass of the girl, m = 25 kg
⟹ Mass of the cart, m' = 10 kg
⟹ initial velocity of the girl, u = 10 m/s
⟹ initial velocity of the cart, u' = 0
⟹ final velocity of girl and cart (system) = v
Now, by law of conservation of momentum
⟹ m * u + m' * u' = (m + m') * v
⟹ 25 * 10 + 10 * 0 = (25 + 10) * v
⟹ 250 = 35 * v
⟹ 35 * v = 250
⟹ v = 250/35
⟹ v = 50/7
⟹ v = 7.1428 m/s (approx)
Answer : The common velocity of the ssyste is 7.1428 m/s.
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