Question

a girl of mass 40 kg jumps with a horizontal velocity of 5 ms onto a stationary cart with friction less wheels. The mass of the cart 3 kg . What is her velocity as the cart start moving? Assume that there is no external unbalanced forc working in horizontal direction? I need verified answer ​

Answer 1

$Given :   Mgirl=40 kg           ugirl=5 m/s        Mcart=3 kg</p><p></p><p> Initial velocity of cart  ucart=0</p><p></p><p>Let the final velocity of cart be  V.</p><p></p><p>Applying conservation of linear momentum :    Pi=Pf</p><p></p><p>Or    Mgirlugirl+Mcartucart=(Mgirl+Mcart)V</p><p></p><p>Or    40×5+3×0=(40+3)V</p><p></p><p>⟹ V=43200 m/s</p><p></p><p>$

i hope it helps Leena

Answer 2

Answer:

A girl of mass 40 kg jumps with a horizontal velocity of 5 m s-1 onto a stationary cart with frictionless wheels. The mass of the cart is 3 kg. What is her velocity as the cart starts moving? Assume that there is no external unbalanced force working in the horizontal direction. NCERT Class IX Sciences - Main Course Book Chapter 9. Force and Laws of Motion

no external force => momentum is constant. momentum of girl = 40 * 5 = 200 kg-m/sec momentum ...

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