Question

. A girl of mass 40 kg jumps with a horizontal velocity of 5 m/s onto a cart of mass

10kg with friction less wheels, which is already moving with a horizontal velocity 1 m/s

in the opposite direction of motion of the girl. What will be the velocity of the girl, when

the cart moves along with her. (Assume that there is no external unbalanced force

working in the horizontal direction)​

Answer 1

Answer:

Given : M

girl

=40 kg u

girl

=5 m/s M

cart

=3 kg

Initial velocity of cart u

cart

=0

Let the final velocity of cart be V.

Applying conservation of linear momentum : P

i

=P

f

Or M

girl

u

girl

+M

cart

u

cart

=(M

girl

+M

cart

)V

Or 40×5+3×0=(40+3)V

⟹ V=

43

200

m/s