Question

a girl of mass 40 kg jumps with a horizontal velocity of 5 m s^-1 onto a stationary cart with frictionless wheels.The mass of the cart is 3kg .What is her velocity as the cart starts moving? Assume that there is no external unbalanced force working in the horizontal direction




Ans.Hope!! this may helps u...
✌✌✌
​

Answer 1

Answer:

M1= 40kg

M2=3kg

U1= 5m/s

U2=0m/s

V1=V2 (as both the obejcts come on top of eachother}

acc to law of conservation of momentum

m1u1+m2u2=m1v1+m2v2

(40×5)+(3×0)=40x+3x

200+0=43x

x= 4.65m/s

velocity=4.65m/s

Answer 2

Answer:

Mass of the girl = 40 kg

Mass of the cart = 3 kg

Velocity of the girl = 5 m/s

Velocity of the cart = 0 m/s

To Find :-

Velocity as the cart starts moving.

Solution :-

Firstly let's find the Mounmentum of girl

[P = mv]

Here,

P = Mounmentum

M = Mass

V = Velocity

P = 40 × 5

Hence, Mounmentum of girl is 200 kg m/s .

Now,

Let's add the Mounmentum of girl and cart

200 + 0 = 200 kg m/s

Let's find total mass

Total mass = 40 + 3 = 43 kg

Velocity=Mounmentum/mass

V = P/M

Velocity = 200/43

Hence :-

Velocity of cart is when start moving is 4.65 m/s.

@ananya........