a girl of mass 40 kg. jumps with a horizontal velocity of 5 m/s onto a stationary cart with frictionless wheels calculate the total momentum just before jumping and just after jumping. also calculate the combined velocity
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jattparv:
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Hey here is your answer
______________________
Given,
A girl of mass = 40 kg
She jumps with a horizontal velocity(v) = 5 m/s
(u) = 0 m/s
Momentum = mass × velocity
The total momentum just before jumping
= 40 × 0 kg m/s
= 0 kg m/s
The total momentum after jumping
= 40 × 5 kg m/s
= 200 kg m/s
The combined velocity
V = u + v
= 0 + 5 m/s
= 5 m/s
___________________________
______________________
Given,
A girl of mass = 40 kg
She jumps with a horizontal velocity(v) = 5 m/s
(u) = 0 m/s
Momentum = mass × velocity
The total momentum just before jumping
= 40 × 0 kg m/s
= 0 kg m/s
The total momentum after jumping
= 40 × 5 kg m/s
= 200 kg m/s
The combined velocity
V = u + v
= 0 + 5 m/s
= 5 m/s
___________________________
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