A girl of mass 40 kg jumps with a horizontal velocity of 5 m/s onto a stationary cart with frictionless wheels .the mass of the cart 3 kg what her velocity as the cart starts moving assume that there is no external unbalanced force working in horizontal direction
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Mass of Girl (M) = 40 Kg
Velocity of Girl (V) = 5 m/s
Mass of Cart = Mass of girl + Mass of cart = 43 Kg
=> MV = mv
=> 40 x 5 = 43 x v
=> 200/43 = v
=> v = 4.65 ms^-1
Velocity of Girl (V) = 5 m/s
Mass of Cart = Mass of girl + Mass of cart = 43 Kg
=> MV = mv
=> 40 x 5 = 43 x v
=> 200/43 = v
=> v = 4.65 ms^-1
Answered by
0
Answer:
Mass of Girl (M) = 40 Kg
Velocity of Girl (V) = 5 m/s
Mass of Cart = Mass of girl + Mass of cart = 43 Kg
=> MV = mv
=> 40 x 5 = 43 x v
=> 200/43 = v
=> v = 4.65 ms^-1
Explanation:
Mass of Girl (M) = 40 Kg
Velocity of Girl (V) = 5 m/s
Mass of Cart = Mass of girl + Mass of cart = 43 Kg
=> MV = mv
=> 40 x 5 = 43 x v
=> 200/43 = v
=> v = 4.65 ms^-1
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