a girl of mass 40 kg jumps with a horizontal velocity of 5m/s into a stationary cart with frictionless wheels.the mass of cart is 10 kg.what is their common velocity as the cart starts moving?
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Answered by
5
Answer:
Hey ☺️✌️
Explanation:
✏️Given : Mgirl=40 kg ugirl=5 m/s Mcart=3 kg
Initial velocity of cart ucart=0
Let the final velocity of cart be V.
Applying conservation of linear momentum : Pi=Pf
Or Mgirlugirl+Mcartucart=(Mgirl+Mcart)V
Or 40×5+3×0=(40+3)V
⟹ V=43200 m/s
✒️ Hope it helps ✌️☺️♥️...
Best wishes ✌️...
Answered by
3
Answer:
Initial velocity=0
let final velocity=V
pi=pf
or 40×5+3×0=(40+3)V
V=43200m/s
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