a girl of mass 40 kg jumps with the horizontal of 5 meter per second on to a stationery cart with the friction less wheels the mass of the cart is 3 kg what is her validity as card start moving ?
Answers
Answered by
0
Explanation:
=(M
girl
+M
cart
)V
Or 40×5+3×0=(40+3)V
⟹ V=
43
200
m/s
Answered by
2
Explanation:
given,
a girl of mass=40 kg
she jumps with horizontal velocity (v)=5m/s
(u)=0m/s
momentum= mass×velocity
the total momentum just before jumping
= 40×0 kg m/s
=0 kg m/ s
the total momentum after jumping
=40 ×5 kg m/s
=200 kg m/s
the combined velocity
V=u. +v
=0+5 m/s
=5m/s
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