Science, asked by manikandan25678, 4 months ago

a girl of mass 40kg stand on her feet of surface area 80cm (g=10m/s) the pressure exerted by her feet is

Answers

Answered by Yuseong
11

Required Answer:

Given:

  • Mass of the girl (m) = 40kg
  • Area (A) = 80cm² = 0.008m²
  • Acceleration (a) = 10m/s²

To calculate:

  • Pressure exerted by her (P)

Calculation:

We know that,

  •  {\underline {\boxed {\Large {\bf \gray { P = \dfrac{F}{A}} }}}}

Where,

  • P = pressure
  • F = force
  • A = area

Let's calculate the force first:

 \sf { \longmapsto F = ma }

 \sf { \longmapsto F = 40 \times 10 }

 \sf { \longmapsto F = 400N }

Therefore, force is 400N.

Now, substituting values in the formula of force:

 \sf { \longmapsto P =\dfrac{F}{A} }

 \sf { \longmapsto P =\dfrac{400}{0.008} }

 \sf { \longmapsto P =\dfrac{400 \times 1000}{8} }

 \sf { \longmapsto P =\dfrac{400000}{8} }

 \boxed{\sf { \longmapsto P = 50,000 \: Pa} }

Therefore, pressure exerted by the girl is 50,000 Pa.

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Extra!

Pressure

  • Pressure is defined as force per unit area.

  • SI unit of pressure is N/m².

  • N/m² is also called 'Pascal'.

  • When the area is large, pressure is less.

  • When the area is small, pressure is more.
  • Formula : P = F/A

  • Dimensional formula of pressure =  \sf { {M}^{1} {L}^{-1} {T}^{-2} }

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