A girl of mass 45 kg is standing on the surface having area of cross section of one shoe as 15cm.square. Find the pressure exerted by her.
NOTE: {p= f/a, f=mass × 10}
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WE KNOW THAT,
PRESSURE=FORCE×AREA⁻¹
HERE,
FORCE=45 Kg
AREA=(15+15)CM=0.3 METER
PRESSURE=45/0.3
=450/3
=150 N/m²
PRESSURE=FORCE×AREA⁻¹
HERE,
FORCE=45 Kg
AREA=(15+15)CM=0.3 METER
PRESSURE=45/0.3
=450/3
=150 N/m²
SWAGGERT:
I tink ur anser is rong, as pressure is written as pascal.
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