a girl of mass 45kg jumps with a horizontal velocity of 4m/s onto a stationary cart with frictionless wheels. the mass of the cart in 5kg. what is his velocity as the cart starts moving
Answers
Answered by
1
Answer:
Given : M
girl
=40 kg u
girl
=5 m/s M
cart
=3 kg
Initial velocity of cart u
cart
=0
Let the final velocity of cart be V.
Applying conservation of linear momentum : P
i
=P
f
Or M
girl
u
girl
+M
cart
u
cart
=(M
girl
+M
cart
)V
Or 40×5+3×0=(40+3)V
⟹ V=
43
200
m/s
Explanation:
Given : M
girl
=40 kg u
girl
=5 m/s M
cart
=3 kg
Initial velocity of cart u
cart
=0
Let the final velocity of cart be V.
Applying conservation of linear momentum : P
i
=P
f
Or M
girl
u
girl
+M
cart
u
cart
=(M
girl
+M
cart
)V
Or 40×5+3×0=(40+3)V
⟹ V=
43
200
m/s
Answered by
0
Answer:
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Explanation:
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