Physics, asked by ahmer6sabri, 1 month ago

A girl of mass 48.0 kg is rescued from a building fire by leaping into a
firefighters' net. The window from which she leapt was 12.0 m above the net.
She lands in the net so that she is brought to a complete stop in 0.45 s. During
this interval (a) What is his change in momentum? (b) What is the impulse on the
net due to the girl? (c) What is the average force on the net due to the girl?
5.103 kom. (DOWN)​

Answers

Answered by Mushkan657
3

Answer:

mgh = 1/2 mv^2

So, v^2 = 9.81*12*2 = 235.44

her momentum upon impact was p = mv = 48 * 15.34 = 736.51 kg-m/s

So, ∆p = -736.51 kg-m/s

maybe you want the rate of change of p. In that case, just divide by 0.45s

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