Question

a girl of mass 50 kg jumps out of a rowing boat of a mass 300 kg on a bank with horizontal velocity of 3 metre per second with what velocity does a Boat begin to move backward

Answer 1

m1=50kg m2=300kg v1=3m/s v2=? we hav 2 find it

conservation of momentum =m1v1+m2v2=0

0 is coz no initial velocity is applied nd de ans will be 50*3+300v2=0

nd i.e v2=-150/300=-0.5m/s so as it is moving in backward direction de velocity (v2) will be 0.5m/s in de backward direction..

Thanks and keep going

Answer 2

Answer:

Explanation:

Initial Momentum = Final momentum

0 = m1u1 + m2u2

u2 = -(m1 u1) / m2

= -(50 kg × 3 m/s) / (300 kg)

= -0.5 m/s

(-ve sign indicates that boat moves backwards)

Velocity of boat will be 0.5 m/s

Have a great day