A girl of mass 50 kg jumps out of a rowing boat of mass 300 kg on to the bank, with a horizontal velocity
of 3 m/s.with what velocity does the boat begin to move backwards?
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Heyaa♡♡
Here is the answer .
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★ Given :
M1=50 kg
m2=300 kg
v1= 3 m/s
v2=?
★ To Find :
Conservation of momentum.
= m1+v1+m2v2+0
0 is because no initial velocity is applied and the answer will be
- 50 x 3 + 300v2=0
- i.e v2 = -150/300=-0.5m/s
★ So , it is moving backward direction the velocity (v2) will be 0.5m/s in the backward direction.
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