Question

A girl of mass 50 kg jumps out of a rowing boat of
mass 300 kg on to the bank, with a horizontal velocity
of 3 m/s. With what velocity does the boat begin to
move backwards ?​

Answer 1

Answer:

Given:-

m₁=50 kg

m₂=300 kg

v₁= 3 m/s

To find:-

v₂ = boat's velocity after the girl jumping off the boat

How to find:-

conservation of momentum

⇒ m₁v₁ + m₂v₂ = 0

0 is because no initial velocity is applied

50*3 + 300*v₂=0

i.e v₂ = -150/300 = -0.5 m/s

So it is moving in the backward direction.

⇒ The velocity (v₂) will be 0.5 m/s in the backward direction.

HOPE IT HELPS YOU

PLEASE MARK ME AS THE BRAINLIEST