Question

A girl of mass 50 kg jumps out of a running boat of mass 300 kg on to the bank, with a horizontal velocity of 3 m/s. With what velocity does the boat begin to move backward?

Answer 1

Answer:

m1=50 kg

m2=300 kg

v1= 3 m/s

v2=?

we have to find.

conservation of momentum=m1+v1+m2v2+0

0 is because no initial velocity is applied and the answer will be  

50 x 3 + 300v2=0

i.e v2 = -150/300=-0.5m/s

so it is moving backward direction the velocity (v2) will be 0.5m/s in the backward direction.

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Explanation: