Question

a girl of mass 50kg jumps out of a boat mass 300kg with horizontal velocity of 3m/s with what velocity does boat begin to move backward ​

Answer 1

Mass of the boat mb = 300 kg

Velocity of boat =vb

Mass of girl mg = 50 kg

Velocity of girl vg = 3 m/s

Acc. to the law of conservation of momentum mb× vb =mg ×vg

300 x vb = 50 x 3

Vb=150/300=1/2=0.5m/s

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Answer 2

Now, momentum of the girl in one direction must be equal to the momentum of the boat in opposite direction. Hence, velocity with which the boat begins to move backwards is 0.5 m/s.