Question

a girl of mass 50kg jumps out of a rowing boat of mass 300kg on to a Bank with a horizontal velocity of 3m/s . with what velocity does the boat begin to move backwards

Answer 1

Initial Momentum = Final momentum
0 = m1u1 + m2u2

u2 = -(m1 u1) / m2
= -(50 kg × 3 m/s) / (300 kg)
= -0.5 m/s
(-ve sign indicates that boat moves backwards)

Velocity of boat will be 0.5 m/s

Answer 2

Answer:

Explanation:

m1=50kg m2=300kg v1=3m/s v2=? we hav 2 find it

conservation of momentum =m1v1+m2v2=0

0 is coz no initial velocity is applied nd de ans will be 50*3+300v2=0

nd i.e v2=-150/300=-0.5m/s so as it is moving in backward direction de velocity (v2) will be 0.5m/s in de backward direction..

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