A girl of mass 65.2kg is travelling at a speed of 18.2 m/s at the top of a 21.5 m high roller coaster loop.
a) Determine the girl's kinetic energy at the top at the loop.
b) Determine the girl's potential energy at the top at the loop.
c) Assuming negligible losses of energy due to friction and air resistance, determine the girl's total mechanical energy at the bottom of the loop ( h = 0 m).
d) Determine the girl's speed at the bottom of the loop. .
Answers
Answered by
5
Answer:
1
Explanation:
K. E. = 1/2 mv²
K. E. = 1/2 ×62.5 ×(21.5)²
Answered by
1
Answer:
a) 15933.850J
Explanation:
KE=1/2mv² = 1/2*65.2*21.5*21.5=34.6*462.25=15933.850
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