Question

A girl of weight 40 N is wearing sandal with heel of area 2 cm square. Find the exerted pressure.

Answer 1

Answer:

F=ma

m=40N,a=10m/s

F=400N

P=F/A

P=400/2×1/100=2×10000 pa

Answer 2

The exerted pressure is 200 kpa.

Explanation:

Given: A girl of weight 40 N is wearing sandal with heel of area 2 cm square.

That means, 40 N is the force.

$= > a = 2 \: {cm}^{2}$

$= > a = \frac{2}{10000} {m}^{2}$

$= > a = 0.0002 {m}^{2}$

Then the exerted pressure is given by

$= > p = \frac{f}{a}$

$= > p = \frac{40}{0.0002}$

$= > p = \frac{40 \times 10000}{2}$

$= > p = 200000 \: pascal$

$= > p = 200 \: kpa$

The exerted pressure is 200 kpa.