A girl of weight 400 N holding a bag of weight 40 N
on her head. If she is standing on semicircular heels
72
of periphery cm, then net pressure exerted on
the floor by the girl is
(1) 3.5x10^5
(2)4.5x10^4
(3) 2.75x10^5
(4) 3.75x10^4
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Answered by
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net pressure exerted on the floor by the girl = 3.5 * 10⁵ N/m²
Step-by-step explanation:
2r + π r = 72/7
=> 2r + 22r/7 = 72/7
=> r + 11r/7 = 36/7
=> 7r + 11r = 36
=> 18r = 36
=> r = 2 cm
She must be Standing on two heels
Area of Both Heels = 2 * ( 1/2) π r² = 88/7 cm²
Force = 400 + 40 = 440 N
Pressure - Force / Area = 440/(88/7)
= 5 * 7
= 35 N/cm²
1 cm² = 10⁻⁴ m²
= 35 / 10⁻⁴ N/m²
= 35 * 10⁴ N/m²
= 3.5 * 10⁵ N/m²
net pressure exerted on the floor by the girl = 3.5 * 10⁵ N/m²
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A girl of weight 400 N holding a bag of weight 40 N on her head. If she is standing on semicircular heels 72 of periphery cm, then net pressure exerted on the floor by the girl is 3.5x10^5.
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