a girl of weight 40kgf is wearing sandal with heel of area 2cm² find the pressure exerted by girlon the ground
Answers
Answered by
10
40kgf = 400N
2cm^2= (2x10^-4) m^2
P=F/A
P=400/(2x10^-4) = (2x10^-2) Pa
amitkolasani:
i corrected it
but the answer shlould not be 2×10^6 pascal
i guess the answer is wrong
ek confusion hai
10^-4 kaise aya
please solve it
P=400/(2x10^-4) = (2x10^6) Pa a small correction
2cm^2 = (2/100x100)m^2 = (2/10^4)m^2 = (2 x 10^-4)m^2
Answered by
18
Hi Mate!!!
PRESSURE = FORCE PER UNIT AREA
I,E FORCE / AREA
Force = 40 kgf = 400N
Area = 2 cm² = 2 × 10 ^ -4 m²
So,. PRESSURE = 400 N / 2 × 10^-4 m²
PRESSURE = 200× 10 ⁴ Pascal.
PRESSURE = 2 × 10^6 Pascal.
!!!! Hope it helps!!!!!
PRESSURE = FORCE PER UNIT AREA
I,E FORCE / AREA
Force = 40 kgf = 400N
Area = 2 cm² = 2 × 10 ^ -4 m²
So,. PRESSURE = 400 N / 2 × 10^-4 m²
PRESSURE = 200× 10 ⁴ Pascal.
PRESSURE = 2 × 10^6 Pascal.
!!!! Hope it helps!!!!!
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